[Q#21438078][A#21438476] How to read char from standard input in Java

https://stackoverflow.com/q/21438078

I have to read char(one at a time) from the standard input in Java.The input will consist of numerous lines (each of about 10000 chars). I do not need to store the chars , they are processed when read.Also I need to skip the newline char .Can someone suggest me an efficient way to do this ?

Answer

https://stackoverflow.com/a/21438476

Perhaps something like this will work:

APIzation

import java.io.IOException;

public class Tester
{
    public static void main(String args[])
        throws IOException
    {
        int ch;
        while ((ch = System.in.read()) != -1)
        {
            if (ch != '\n' && ch != '\r')
            {
                processChar((char)ch);
            }
        }
    }


    private static void processChar(char c)
    {
        // do stuff
        System.out.println("Processing: '" + c + "'");
    }

}

package com.stackoverflow.api;

import java.io.IOException;

public class Human21438476 {

  public static void processStandardInput() throws IOException {
    int ch;
    while ((ch = System.in.read()) != -1) {
      if (ch != '\n' && ch != '\r') {
        processChar((char) ch);
      }
    }
  }

  private static void processChar(char c) {
    // do stuff
    System.out.println("Processing: '" + c + "'");
  }
}

package com.stackoverflow.api;

import java.io.IOException;

/**
 * How to read char from standard input in Java
 *
 * @author APIzator
 * @see <a href="https://stackoverflow.com/a/21438476">https://stackoverflow.com/a/21438476</a>
 */
public class APIzator21438476 {

  public static void readChar() throws IOException {
    int ch;
    while ((ch = System.in.read()) != -1) {
      if (ch != '\n' && ch != '\r') {
        processChar((char) ch);
      }
    }
  }

  private static void processChar(char c) {
    // do stuff
    System.out.println("Processing: '" + c + "'");
  }
}